Setting up a triple integral using cylindrical & spherical coordinates

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The discussion focuses on setting up a triple integral for a region inside a sphere defined by x² + y² + z² = R², constrained between the planes z = R/2 and z = R. Participants confirm that the upper limit for r in cylindrical coordinates is correct and clarify that the lower limit for z should be R/2. In spherical coordinates, it is noted that the lower limit for ρ will depend on the angle φ, which is an important concept to understand. There is also a discussion about an unnecessary factor of 2 in the integral, with advice to trust one's instincts regarding its inclusion. Overall, the conversation emphasizes the correct setup of limits for the integrals in both coordinate systems.
calcuseless
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Homework Statement



Inside the sphere x2 + y2 + z2 = R2 and between the planes z = \frac{R}{2} and z = R. Show in cylindrical and spherical coordinates.

Homework Equations



\iiint\limits_Gr\,dz\,dr\,d\theta

\iiint\limits_G\rho^{2}sin\,\theta\,d\rho\,d\phi\,d\theta

The Attempt at a Solution



2\int_0^{2\pi}\int_0^{R\sqrt{\frac{3}{4}}}\int_?^{\sqrt{R^{2}-r^{2}}}r\,dz\,dr\,d\theta
Is my upper limit for r correct? How do I find the lower limit for z?

\int_0^{2\pi}\int_0^{\frac{\pi}{3}}\int_?^R\rho^{2}sin\,\theta\,d\rho\,d\phi\,d\theta
How do I find the lower limit for rho?
 
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calcuseless said:

Homework Statement



Inside the sphere x2 + y2 + z2 = R2 and between the planes z = \frac{R}{2} and z = R. Show in cylindrical and spherical coordinates.

Homework Equations



\iiint\limits_Gr\,dz\,dr\,d\theta

\iiint\limits_G\rho^{2}sin\,\theta\,d\rho\,d\phi\,d\theta

The Attempt at a Solution



2\int_0^{2\pi}\int_0^{R\sqrt{\frac{3}{4}}}\int_?^{\sqrt{R^{2}-r^{2}}}r\,dz\,dr\,d\theta
Is my upper limit for r correct? How do I find the lower limit for z?

Yes the upper limit is OK. Isn't the equation of the plane z = R/2? That would be z on the lower surface.

\int_0^{2\pi}\int_0^{\frac{\pi}{3}}\int_?^R\rho^{2}sin\,\theta\,d\rho\,d\phi\,d\theta
How do I find the lower limit for rho?

Again, the equation of that plane is z = R/2. Express that in spherical coordinates and solve it for \rho. You will find that \rho depends on \phi, but that's OK.
 
LCKurtz said:
You will find that \rho depends on \phi, but that's OK.

Ah, I didn't understand that concept. Thank you!

2\int_0^{2\pi}\int_0^{R\sqrt{\frac{3}{4}}}\int_\frac{R}{2}^{\sqrt{R^{2}-r^{2}}}r\,dz\,dr\,d\theta
Is there supposed to be a 2 out in front? I don't know why I put it there and I don't think it is needed for this problem.
 
calcuseless said:
2\int_0^{2\pi}\int_0^{R\sqrt{\frac{3}{4}}}\int_\frac{R}{2}^{\sqrt{R^{2}-r^{2}}}r\,dz\,dr\,d\theta
Is there supposed to be a 2 out in front? I don't know why I put it there and I don't think it is needed for this problem.

I don't know why you put it there either. Go with your instincts. If you don't think it should be there, don't put it there. :cool:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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