Shaft Sizing: Calculating σmax from 1045 UTS/YTS

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To calculate σmax for 1045 steel using the provided formula, it can be approximated by using the yield strength (YTS) of 74300 psi as a rough estimate. The formula D = 1.72 (Tmax/σmax)^1/3 is designed for ductile materials under static, pure shear conditions. It's important to note that this approach assumes a specific relationship between shear and normal stresses. For more accurate results, consider additional factors that may affect the material's performance. Understanding these calculations is crucial for effective shaft sizing in engineering applications.
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Attempting to use the formula:
D = 1.72 (Tmax/σmax)^1/3

In my case I do not know σmax or at least how to calculate it from material properties.
Material is 1045
UTS 84800
YTS 74300
Tmax = 591.55 in-lbs

D = 1.72 (Tmax/σmax)^1/3

Any help would be appreciated.

Regards
 
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As a very rough pass, you can use your yield strength as \sigma_{max}. Your equation is essentially assuming a set relationship for ductile materials and the relationship between shear stresses and normal stresses. This is for static, pure shear only.
 

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