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Coordinate velocity of the beam is slowed down in a gravity field, except for the straight down component of the coordinate velocity?

Some part of the trip takes a long time anyway.

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Coordinate velocity of the beam is slowed down in a gravity field, except for the straight down component of the coordinate velocity?

Some part of the trip takes a long time anyway.

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Nugatory

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No. The Shapiro delay is caused by the distance between source and emitter being longer when a substantial (no need for it to be black hole) mass is nearby. Light still travels at speed c, but it has longer to go when the mass curves the space between source and emitter, so it takes longer to make the same journey.Why is there a large Shapiro delay when a light beam passes a black hole?

Coordinate velocity of the beam is slowed down in a gravity field, except for the straight down component of the coordinate velocity?

(A fair case could be made this question belongs in a different thread)

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The radar distance between black hole photon sphere and black hole event horizon is infinite, according to an observer at photon sphere.

The radar distance between black hole photon sphere and black hole event horizon is zero, according to an observer at rest at event horizon.

A radar beam sent towards the event horizon reaches the event horizon in finite time, according an outside observer.

A radar beam sent outwards from the event horizon will not reach an outside observer in finite time.

Right?

It seems like the space around a large mass is such kind of space that the distance from A to B is larger than the distance from B to A, if A is located below B.

The radar distance between black hole photon sphere and black hole event horizon is zero, according to an observer at rest at event horizon.

A radar beam sent towards the event horizon reaches the event horizon in finite time, according an outside observer.

A radar beam sent outwards from the event horizon will not reach an outside observer in finite time.

Right?

It seems like the space around a large mass is such kind of space that the distance from A to B is larger than the distance from B to A, if A is located below B.

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Dale

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Yes, or any other radius r>R.The radar distance between black hole photon sphere and black hole event horizon is infinite, according to an observer at photon sphere.

There is no such observer.The radar distance between black hole photon sphere and black hole event horizon is zero, according to an observer at rest at event horizon.

What do you mean by "time according to an outside observer" as applied to events on the horizon?A radar beam sent towards the event horizon reaches the event horizon in finite time, according an outside observer.

Yes.A radar beam sent outwards from the event horizon will not reach an outside observer in finite time.

It depends how you define the distances.It seems like the space around a large mass is such kind of space that the distance from A to B is larger than the distance from B to A, if A is located below B.

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Nugatory

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No, what your example shows is that under the conditions of that example (which is only vaguely related to the Shapiro delay) those distances are not easily defined.It seems like the space around a large mass is such kind of space that the distance from A to B is larger than the distance from B to A, if A is located below B.

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A.T.

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It's not just the spatial distortion (more distance), but also gravitational time dilation (slower light according to distant clock).The Shapiro delay is caused by the distance between source and emitter being longer when a substantial (no need for it to be black hole) mass is nearby.

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PAllen

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No, it is sort of either/or, take your pick. The invariant observation is the delay. Pick one set of coordinates, and you have pure distance distortion; pick another and you have pure coordinate lightspeed change; or pick a mixture with funky coordinates.It's not just the spatial distortion (more distance), but also gravitational time dilation (slower light according to distant clock).

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Posts here also give some nice insights:

Energy shift in a photon passing by a gravitational well

https://www.physicsforums.com/showthread.php?t=690006&highlight=shapiro+delay

Like Pallen just posted here in #7 while I was typing....

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A.T.

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What about Schwarzschild coordinates?Pick one set of coordinates, and you have pure distance distortion; pick another and you have pure coordinate lightspeed change; or pick a mixture with funky coordinates.

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MTW works out the shapiro delay on pg 1107 in PPN coordinates. These are basically the same as isotropic coordinates (not the usual schwarzschild) - though the surfaces of time simultaneity will be the same for isotropic and schwarzschild coordinates.What about Schwarzschild coordinates?

They use the cartesian form of the isotropic / ppn coordinates (dt, dx, dy, dz).

MTW's derivation is approximate - they spend some time explaining why assuming light travels in a straight line in PPN coordinates (rather than the actual curved and not time-invariant path it actually follows) gives small errors, due to Fermat's principle.

The basic answer they get with these approximations is:

[tex]

t_{TR} = \int_{-a_t}^{a_r} \left( \frac{g_{xx}}{-g_{tt}} \right) ^ {\frac{1}{2}} \, dx

[/tex]

where ##-a_t## and ##a_r## are the x-coordinate positions in the ppn system. (There is a parameter b in the result which is the constant y-coordinate in the ppn system as well). These are hard to observe, a later formula eliminates them by considering the rate of change of the Shapiro delay.

I would say that the answer that bests fits the above derivation is "both". Certainly we see ##g_{tt}## there, we also see the spatial terms ##g_{xx}##. It's a bit hard to summarize this in the simplistic way the thread is being discussed :-(.

[add]

Probably the best simple answer is not an answer, but another question, i.e. to ask "what do you really mean by distance? in GR? How are you measuring it?".

There is certainly no conflict with the notion that the notion of proper distance is based on a constant speed of light though, which seems to be the thrust of the question. But the details of carrying out the calcuation (even with an approximation) typically involve setting up a coordinate system, using changes in coordinates (dx - which isn't a distance), and calcuating the proper time by using the coordinate change dx and the non-constant coordinate speed of light (the number in the square root).

MTW makes a few more approximations, and subtract out a Newtonian part, and get an answer that depends only on the ppn parameter ##\gamma##

There may or may not be other ways of calculating it, this is what my textbook does though.

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A.T.

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That was my point.I would say that the answer that bests fits the above derivation is "both". Certainly we see ##g_{tt}## there, we also see the spatial terms ##g_{xx}##.

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PAllen

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In SC coords, coordinate light speed plays a role. But in radar coordinates, the same prediction is purely from spatial distortion.What about Schwarzschild coordinates?

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When one computes this distance by means of coordinates, we can see from the above example that the coordinate expression of gravitational time dilation and the coordinate expression of spatial curvature both play a role in computing the distance in that coordinate system. However, this should not be interpreted as the local speed of light varying - the local speed of light is always equal to c. Furthermore we note that the distance (by this definition) really does increase when the connecting curve passes near a massive object - again the point is not to "throw away" the fundamental notion that the speed of light when measured locally is a constant.

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The horizontal coordinate velocity of light (travelling at constant radius from the gravitational centre) is slower than the local horizontal speed of light, by a factor of sqrt(1-2m/r) in the Schwarzschild metric, which is purely due to gravitational time dilation. The vertical component of the coordinate speed of light that is slower by a factor of (1-2m/r), which you can think of as a slow down due to gravitational time dilation by a factor of sqrt(1-2m/r) and an additional factor of sqrt(1-2m/r) due to spatial distortion.... Coordinate velocity of the beam is slowed down in a gravity field, except for the straight down component of the coordinate velocity?

Some part of the trip takes a long time anyway.

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A.T.

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Yes, according to a local clock. But the whole point of the Shapiro delay is what duration a distant observer measures with his clock.the local speed of light is always equal to c.

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What do you mean by "time according to an outside observer" as applied to events on the horizon?

Let me think ... I mean we have clocks with gravitational time dilation elimination mechanism, these clocks, when lowered slowly to various altitudes, can be used to measure times.

As an example of such clocks: light clocks that shrink in such a way that gravitational time dilation is cancelled.

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