Shell Method Question - Where am I wrong?

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SUMMARY

The discussion focuses on calculating the volume of a solid formed by rotating the area between the function y=xe^(0.5x) and the x-axis from x=0 to x=2 about the line x=-2 using the Shell Method. The correct formula applied is Vs = ∫ 2∏r * f(x) with r defined as r = x + 2. The final volume computed is 16∏(e^1 - 1) ≈ 86.3703, which is confirmed as accurate by participants in the discussion.

PREREQUISITES
  • Understanding of the Shell Method for volume calculation
  • Familiarity with integration techniques in calculus
  • Knowledge of exponential functions and their properties
  • Ability to evaluate definite integrals
NEXT STEPS
  • Review the Shell Method for different axis of rotation
  • Practice integration of exponential functions using integration by parts
  • Explore applications of volume calculations in real-world scenarios
  • Learn about alternative methods for volume calculation, such as the Disk Method
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Students studying calculus, particularly those focusing on volume calculations and the Shell Method, as well as educators looking for examples of integration techniques.

Bellwether
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Homework Statement



Find the volume of the solid created when the area between the function y=xe0.5x and the x-axis (for 0≤x≤2) is rotated about the line x=-2

Homework Equations



Shell Method: Vs = ∫ 2∏r * f(x)

The Attempt at a Solution



r = x + 2

r * f(x) = x2e0.5x + 2xe0.5x

Thus, 2∏∫ (x2e0.5x + 2xe0.5x)dx {from 0 to 2}

My final answer is 16∏(e1 - 1) ≈ 86.3703

Did I make a mistake somewhere?
 
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It looks correct.
 

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