Short cut tricks to find resistance of large/messed resistance's network.

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Discussion Overview

The discussion revolves around methods for calculating the equivalent resistance in complex resistor networks, particularly those with symmetrical properties. Participants explore various shortcut tricks derived from Kirchhoff's laws and seek proofs or derivations for these methods.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant outlines several shortcut tricks for finding equivalent resistance in symmetrical resistor networks, including conditions related to symmetry and current flow.
  • Another participant questions the validity of the claim that resistances on the axis of symmetry can be removed without affecting equivalent resistance, suggesting a need for further clarification.
  • Some participants express confusion regarding the reasoning behind certain claims, particularly the implications of symmetry on current and resistance.
  • There is a mention of a Wheatstone bridge as a specific case where removing a resistor does not affect the equivalent resistance, but this is challenged as being too narrow an example.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the validity of the shortcut tricks or the implications of symmetry in resistor networks. There are competing views on the applicability of certain claims, particularly regarding the removal of resistors and the behavior of current in symmetrical configurations.

Contextual Notes

Some participants express uncertainty about the proofs or derivations of the proposed shortcuts, indicating a lack of clarity in understanding the underlying principles. The discussion highlights the complexity of applying symmetry in circuit analysis.

vkash
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Today our physics teacher teach us how to find resistance of a network of resistance that is messed to heavily(example all sides of a cube are resistance find resistance). Ok those are very good methods, but it seems that they are not result of experiments done by genius persons it seems that they are derived from Kirchoff's laws of loops. Can you please tell me the proof or something like this for their tricks these short cut tricks.
these short ct tricks are
(1)If in a network of resistances line joining terminals in an axis of symmetry then
(a) corresponding same point will carry same current.
(b) If network is folded about this axis of symmetry then equivalent resistance does not change.
(2)If in a network of resistances the perpendicular bisector of joining terminals is axis of symmetry then
(a) corresponding points will have same current but their directions will be different with respect to axis of
symmetry.
(b) If a resistance is lying on the axis of symmetry then it can removed without changing equivalent
resistance.
(c) all the points lying on this point will have same potential.
(3) If in network of resistances if all the resistances are became n times then net resistance will n times.
I don't ask him(teacher) for these proofs/derivations because like every time he will say " Proofs never come in examination so what's gain of learning those proofs or derivations."
After all i hope you will not reply so.

thanks for reading. make reply if you know anything about it.double thanks to repliers.
 
Last edited:
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Does non of you know it's answer??
If their is any problem understanding question then tell me i will try to make it clear.
 
vkash said:
Does non of you know it's answer??
If their is any problem understanding question then tell me i will try to make it clear.
I post it here bcz i thought there are some persons whichc will think on it. I think none of you think.Howeveri think a bit and want to share it with you.
explanation for
1(a) let us assume that there is different current in upward upper and lower part of circuit. Now just reverse the direction of the circuit i mean upper part in lower and lower in upper. So the current slowing in upper part will now the current in lower part and current flowing in lower part willl in upper part. BUT the circuit is same as it was before reversing. So here arise contradiction which can killed if and only current in upper and lower region will same.
1(b) still now i have no idea for this.
2(a) It is much similar to 1(a) but in this case we require to revert the direction of current. If we take current different then contradiction will arise which can be cured only by taking current similar.
2(b) It is derivative of 2(a)
2(c) doesn't get;
2(d) One more thing that i can't explain.

hey friends please help yar;Tell me something that how it can.
 
(b) If a resistance is lying on the axis of symmetry then it can removed without changing equivalent
resistance.

Perhaps you should have another chat with your advisor?

Look at the following circuit and ask yourself if the equivalent resistance between A and B is unaffected by removing Rs.

go well
 

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Studiot said:
Perhaps you should have another chat with your advisor?

Look at the following circuit and ask yourself if the equivalent resistance between A and B is unaffected by removing Rs.

go well
This is wheat stone bridge. It is not affected by Rs.But think this is not the way of explaining any thing. I mean 2*2=4 and2+2=4. It does not mean that * is same as +.
How you can explain all the phenomena by one example. It's particular case.
 

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