Should I consider internal forces for this hinged structure?

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SUMMARY

The discussion centers on the analysis of a hinged structure subjected to a 20 N load at point C and the implications of internal forces on moment equations. Participants confirm that the moment equations for both situations are valid, provided the direction of force F is correctly identified as vertically downward. The introduction of an additional rod in the second situation does not affect the moment equation if it acts as a 0-rod, which transmits force without contributing additional internal forces. Ultimately, internal forces do not need to be considered for calculating the required force F using a moment equation about point A.

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  • Understanding of moment equations in structural analysis
  • Knowledge of hinged structures and their load distribution
  • Familiarity with the concept of 0-rods in structural mechanics
  • Ability to identify force directions in mechanical systems
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Summary:: A hinged structure applied with a load, should the structure totally been calculated in order to find the resultant force?

Hello,

Two situations, the first is a simple structure with a 20 N load at point C. The moment-equation is composed next to it.

Second situation:
A hinged structure is again loaded with 20 N. A moment-equation can also been found next to it.

For both situations,
  • Are the moment-equations correct? Or should I take internal forces also in consideration?
  • Would a 'extra' rod drawn in situation 2 affect the moment-equation?
  • Could situation 2 be simplified? I was thinking about kind of a 0-rod (see sketch). That is in line with the force so it actually does nothing more than passing a force.

1624214599916.jpeg


Mentor note: Moved from engineering forum, so no template.
 
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The momentum equation is fine, but how dit you determine the direction of F? If E is a pin joint, DE will rotate until it is in the line of F.

Same question for situation 2. If F is in the same direction as DE, the new rod has no forces. if E is a pin joint this should happen. If you don't know what α is, you can't solve it.
 
willem2 said:
The momentum equation is fine, but how dit you determine the direction of F?
I see, I think I made a mistake there. Force F should be vertically down instead, this would make more sense.

willem2 said:
If F is in the same direction as DE, the new rod has no forces. if E is a pin joint this should happen.
This makes sense :). That would make rod AE a 0-rod.

With this information, I think I can say the internal forces doesn't need to be considered. If I want to calculate the needed Force F, I can apply a moment-equation about point A?
 

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