Should You Add dy to the Line Integral Expression?

-Vitaly-
Messages
39
Reaction score
0

Homework Statement


Hello, I'm writing a summary of all calculus I've learned during this term and now I'm on line integrals. I wrote this so far:
http://img17.imageshack.us/img17/9776/algebrac.jpg
But I have Sigma of x and y (a similar expression was in my lecture notes), but there is no dy anywhere, do I need to add dy to that expression? or just treat y as a constant? (if line density is given as a function of x and y)

Homework Equations



The Attempt at a Solution

 
Last edited by a moderator:
Physics news on Phys.org
There is no real y-dependence. Remember that the shape of the chain is given as some function of x. So, given x, what should y be?
 
Galileo said:
There is no real y-dependence. Remember that the shape of the chain is given as some function of x. So, given x, what should y be?
Oh, so just rearrange y in terms of x :D Thanks
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top