Show Limit Theorem: Sum of Sequence is L

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Homework Statement


Suppose that a_n->L as n->infinity. Show that (a1+a2+...+an)/n=L as well.


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The Attempt at a Solution


I'm thinking something about limit theorems here?
 
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use the definition. note that |(a1+a2+...+an)/n-L| = |((a1-L)+...+(an-L))/n|, and I guess you know something about the behavior of |a_n-L| when n goes to infinity :)
hope this helps u
 
Sheesh, should have seen that. Thanks!
 
economist1985 said:
Sheesh, should have seen that. Thanks!

No, you shouldn't have seen that. That's not a proof at all. You need to go back to epsilons and deltas for this one.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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