Show ψ(x,t) = f(x-at) + g(x+at) satisfies the wave equation

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SUMMARY

The discussion focuses on demonstrating that the function ψ(x,t) = f(x-at) + g(x+at) satisfies the wave equation a²(∂²ψ/∂x²) - (∂²ψ/∂t²) = 0. Participants emphasize the importance of applying the chain rule for differentiation, specifically using the substitutions u = x - at and v = x + at. The correct application of the second derivatives with respect to both x and t is crucial, as both derivatives must be computed accurately to validate the wave equation. The clarification that both second derivatives must be taken with respect to x and t is also highlighted as a key point in the solution process.

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Homework Statement



Show ψ(x,t) = f(x-at) + g(x+at) satisfies the wave equation (a^2)*(∂^2ψ/∂x^2)-(∂^2ψ/∂x^2)=0

Homework Equations





The Attempt at a Solution



I think i just take the derivative twice and end up with something like the second derivative = a^2*second derivative. However how do I actually take the derivative of an equation like this? I know it will involve the chain rule, but how exactly? Thanks for any help.
 
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Your f(x-at), set:
y=f(u)
u=x-at

Chain rule: dy/dx=dy/du*du/dx
dy/dx=f'(u)*1

This is how you can differentiate your function, same goes for differentiating to t.
If all goes well, the f'(u) should cancel out.
Also, you have the wrong wave equation there; both differentials are with respect to x. One should be to t.

Hope this helps.
 

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