Show that Tv^(R/c_v) = constant

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SUMMARY

The discussion centers on the derivation of the equation Tv^(R/c_v) = constant, starting from the relationship c_v = (dT/dV)_s = -[(du/dv)_T + P]. Participants explore the thermodynamic identities involving internal energy (u), temperature (T), and specific heat capacity at constant volume (C_v). The equation Tds - Pdv = C_vdT + (∂u/∂v)dv is established, linking changes in entropy (s) and volume (v) to temperature and internal energy. This foundational understanding is crucial for further thermodynamic analysis.

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Homework Statement
The equation of state of a certain gas (P+b)v=RT and its specific internal energy u is given by u=aT+bv+u_0 where a ,b, u_0 and R are constants.
a) Find c_v (DONE)
b) Show that c_p - c_v =R for this gas (DONE)
c) Using the equation in (b) show that Tv^(R/c_v) = constant
Relevant Equations
(P+b)v=RT
u=aT+bv+u_0
The solutions start from the fact that c_v= (dT/dV)_s = -[(du/dv)_T + P], however I cannot reason where did that come from. Any help will be appreciated.
 
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$$du=Tds-Pdv=\frac{\partial u}{\partial T}dT+\frac{\partial u}{\partial v}dv=C_vdT+\frac{\partial u}{\partial v}dv$$so
$$Tds-Pdv=C_vdT+\frac{\partial u}{\partial v}dv$$
 
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