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## Homework Statement

A cylindrical disk of wood weighing 47.0 N and having a diameter of 30 cm floats on a cylinder of oil of density 0.850 g/cm^3 (the figure). The cylinder of oil is 75.0 cm deep and has a diameter the same as that of the wood.

a) What is the gauge pressure at the top of the oil column?

b) Suppose now that someone puts a weight of 88.0 N on top of the wood, but no oil seeps around the edge of the wood. What is the change in pressure at the bottom of the oil?

c) What is the change in pressure at the halfway down in the oil?

## The Attempt at a Solution

a) [tex]P=\frac{F}{A} \Rightarrow P=\frac{47.0 \mathrm{N}}{.071 \mathrm{ m}^3}=665 \mathrm{ Pa}[/tex]

this answer is correct

b) why would the pressure change at the bottom not be equal to the pressure change at top. i.e 1245 Pa - 665 Pa?

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