- #1

#### helix

Okay, is it just me, or does this problem seem way to easy to be worth 100 pts?

It's -3.54N, right? Is the weight of the wagon irrelevant?

Thanks!

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- Thread starter helix
- Start date

- #1

Okay, is it just me, or does this problem seem way to easy to be worth 100 pts?

It's -3.54N, right? Is the weight of the wagon irrelevant?

Thanks!

- #2

Staff Emeritus

- 1,901

- 3

I can't stress enough how helpful a picture is. Label all the forces and draw their components. Once you are confident that the picture is correct then procede to sum the forces in the x and y and/or z direction, setting the lefthand side to either 0 or m*a.

- #3

Science Advisor

Homework Helper

- 43,008

- 974

Assuming that the woman is pulling the bag at a constant speed, the horizontal acceleration is 0 and there must be no net horizontal force. The friction force is exactly the horizontal component of force the woman is applying and oppositely directed.

I get exactly the same answer you do. Since you are told what the mass of the bag is, you could calculate its weight and then find the coefficient of friction from the information given.

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