# Simple Harmonic Motion of a gun

(1)It takes a force of 75 N to compress the spring of a toy popgun 0.18 m to "load" a 0.14 kg ball. With what speed will the ball leave the gun?

I used the equation F=kx
I solved for K and I got 416 N/m

Then I used the equation omega = square root(K/M)
I solved for omega and i got 54.5.

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Hint: This is not a S.H.M. problem.
f= -k*x
k>> 416 N/m
This is not necessary.

The spring energy is converted into kinetic energy. Do you know what the spring energy is now that you know K? Can you figure out the velocity with this?

Thank you both for your help. I'm still not sure if I completely understand this problem

PE= 1/2kx^2
where I know k because it is 416 N/M and X=.18. so I would solve for the PE.

Then you're saying if the spring energy is converted to kinetic energy, then is KE=PE?
thus KE= 1/2mv^2 and then I would have to solve for v?

But I still don't think this is right because where is the 75N coming in?

You used it to find K, did you not?

Yeah, I'm an idiot. Thanks for your help.