Simple harmonic motion platform

AI Thread Summary
A platform is undergoing simple harmonic motion with a 5 cm amplitude and a frequency of 10/pi vibrations per second. The discussion focuses on determining when a block, initially placed at the lowest point, will leave the platform and how high it will rise above the platform's highest point. The angular frequency was calculated to be 20 rad/s, and the equations of motion were discussed, particularly the condition for the block to leave the platform. A participant clarified that the problem asks for the position rather than the time, leading to a resolution of the problem. The conversation highlights the importance of understanding the relationship between motion parameters in simple harmonic motion.
Thatonetim194
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1. A platform is executing simple harmonic motion in a vertical direction with an amplitude of 5 cm and a frequency of 10/pi vibrations per second. a block is placed on the platform at the lowest point of its path.
a) at what point will the block leave the platform?
b)how far will the block reach above the highest point that the platform reaches

2. Homework Equations

x=Acos(ωt-phi)
mg=-ma(where the block leaves the platform)
g-(ω^2)Acos(ωt)=0
ω=2pif
m(g-(ω^2)Acos(ωt))=0

3. The Attempt at a Solution for part a

given the frequency i found the angular frequency to be 20rad/s

knowing x=-Acos(ωt) because it starts out at the lowest point at -A and also no phase angle to the equation.

to find when the mass leaves the platform -ma=mg, and taking the derivative twice of this equation a=(ω^2)Acos(ωt)

and i need to satisfy the initial condition of the acceleration so i get m(g-(ω^2)Acos(ωt))=0

but how do find when this happens?

part b I was not able to get to yet
 
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Thatonetim194 said:
1. A platform is executing simple harmonic motion in a vertical direction with an amplitude of 5 cm and a frequency of 10/pi vibrations per second. a block is placed on the platform at the lowest point of its path.
a) at what point will the block leave the platform?
b)how far will the block reach above the highest point that the platform reaches

2. Homework Equations

x=Acos(ωt-phi)
mg=-ma(where the block leaves the platform)
g-(ω^2)Acos(ωt)=0
ω=2pif
m(g-(ω^2)Acos(ωt))=0

3. The Attempt at a Solution for part a

given the frequency i found the angular frequency to be 20rad/s

knowing x=-Acos(ωt) because it starts out at the lowest point at -A and also no phase angle to the equation.

to find when the mass leaves the platform -ma=mg, and taking the derivative twice of this equation a=(ω^2)Acos(ωt)

and i need to satisfy the initial condition of the acceleration so i get m(g-(ω^2)Acos(ωt))=0

but how do find when this happens?

Don't they ask the position (they say "at what point"), not the time? Then you just need - Acos(ωt), no?
 
Just to let people know I actually found out how to do the problem sorry for posting this.
 
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