Simple harmonic motion problem.

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Homework Help Overview

The discussion revolves around a simple harmonic motion problem involving a car's oscillation, described by the equation x = x₀cos(2πt/T). Participants are tasked with finding expressions for velocity and acceleration, as well as determining their maximum values given specific parameters.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss differentiating the position function to find expressions for velocity and acceleration. There is uncertainty regarding the expression for velocity and the role of time (t) in the calculations. Some participants suggest using maximum values of sine and cosine to simplify the problem.

Discussion Status

Several participants have provided hints and guidance on how to approach finding the expressions for velocity and acceleration. There is an ongoing exploration of the maximum values of these quantities, with some participants questioning their previous calculations and assumptions about the use of sine and cosine functions.

Contextual Notes

Participants express confusion regarding the unknowns in the problem, particularly the time variable (t) and how it affects the calculations for maximum velocity and acceleration. There is also mention of homework constraints that may influence the approach taken.

hot2moli
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x=xocos(2pi t/T), where xo is the maximum amplitude of oscillation and T is the period of oscillation.

Find expressions for the velocity and acceleration of a car undergoing simple harmonic motion by differentiating x.
[Answer: a=–(2pi/T)^2(Xo)cos(2pi t/T).]

QUESTION:
If xo = 0.3 m and T = 3 s, what are the maximum values of velocity and acceleration?


I do not know the expression for velocity. ANNDD I do not know (t), so even just solving for acceleration I have a problem because I face two unknowns.
 
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If you found the expression for acceleration, then you should be able to find the expression for velocity.

HINT: Take one less derivative.

For the maximum values, you have to plug in the maximum values of cosine and sine (whichever one appears in the formula) So, the question becomes, what are the maximum values for sine and cosine? Remember, the argument of the sine or cosine shouldn't matter.
 
Recall that for any oscillation, A*cos(something) or A*sin(something) that A is the maximum value that it can possibly have since cos/sin can only go as high a "1". This is why "A" is called the amplitude of the oscillation.

Find velocity and acceleration by simply finding the first derivative of x with respect to t and the second derivative with respect to t. Whatever is out in front of those sinusoids are the max values.
 
so I can disregard sine/cos since it would just be -1/1... therefore I only focus on the bginning of the equation

a=–(2pi/T)^2(Xo)

And i would just plug in getting 1.3m/s2 but that is incorrect..
 
and then would velocity just be:
2(2pi/T) = Vmax
 
hot2moli said:
so I can disregard sine/cos since it would just be -1/1... therefore I only focus on the bginning of the equation

a=–(2pi/T)^2(Xo)

And i would just plug in getting 1.3m/s2 but that is incorrect..

Try dropping the negative sign. They are probably looking for the absolute maximum acceleration.

hot2moli said:
and then would velocity just be:
2(2pi/T) = Vmax

This is not correct. The answer should involve x_o.
 

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