x=xocos(2pi t/T), where xo is the maximum amplitude of oscillation and T is the period of oscillation. Find expressions for the velocity and acceleration of a car undergoing simple harmonic motion by differentiating x. [Answer: a=–(2pi/T)^2(Xo)cos(2pi t/T).] QUESTION: If xo = 0.3 m and T = 3 s, what are the maximum values of velocity and acceleration? I do not know the expression for velocity. ANNDD I do not know (t), so even just solving for acceleration I have a problem because I face two unknowns.