Simple Harmonic Motion: Question about w(t+T)=wt+2pi

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The discussion centers on the equation w(t+T) = wt + 2π in the context of simple harmonic motion. It clarifies that T represents a time interval after which the motion repeats, leading to the conclusion that cos(ω(t+T)) equals cos(ωt). The relationship ω(t+T) - ωt = 2π implies that ωT equals 2π, confirming the periodic nature of the motion. The initial confusion arose from the assumption that ω would distribute in the first expression. Ultimately, the clarification resolves the misunderstanding about the periodicity in simple harmonic motion.
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I have a quick question about simple harmonic motion. My text states this in the picture attached, and I'm confused as to why:

w(t+T) = wt+2pi
wT=2pi

I assumed w would distribute out into the first expression. I know this may be a dumb question but please help because it is bothering me.
ImageUploadedByPhysics Forums1389914137.865893.jpg


Thank you!
 
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hi xtrubambinoxpr! :smile:
xtrubambinoxpr said:
w(t+T) = wt+2pi
wT=2pi

I assumed w would distribute out into the first expression.

T is defined as being the time difference after which everything is the same.

So cos(ω(t+T)) = cos(ωt).

So ω(t+T) - ωt = 2π, ie ωT = 2π. :wink:
 
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tiny-tim said:
hi xtrubambinoxpr! :smile:


T is defined as being the time difference after which everything is the same.

So cos(ω(t+T)) = cos(ωt).

So ω(t+T) - ωt = 2π, ie ωT = 2π. :wink:


i see my mistake! thanks!
 
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