Simple integration help needed work shown!

  • Thread starter johnq2k7
  • Start date
  • #1
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Evaluate the integral below:

2Pi times the integral of (2-y^2)(sqrt(1+4y^2)) dy from 0 to sqrt(2)

work shown:

using integration by parts I got:

let u= sqrt(1+4y^2)

therefore du= 4y/(4y^2+1)

let dv= (2-y^2)

therefore V= 2y- y^3/3

since Integration by Parts is (u)(V) - integral of (V)(du)

therefore i got 2*Pi times (sqrt(1+4y^2)(2y-y^3/3) - integral of (2y-y^3/3)(4y/sqrt(4y^2+1)) dy from 0 to sqrt (2)

after evaluating this i keep getting a more completed integration by parts.. and continous iteration.. please help me solve this integral
 

Answers and Replies

  • #2
2,342
677
Looks like you messed up du.
 
  • #3
64
0
Looks like you messed up du.

i believe my du is correct, even so... i believe my integration by parts method is tedious and it won't result in a solution.. i believe i'm using the wrong method to integrate this equation... please help
 

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