Simple Nodal Analysis

  • Thread starter ravenprp
  • Start date
  • #1
ravenprp
74
0

Homework Statement



http://img258.imageshack.us/img258/2152/screenshot01kf5.th.jpg [Broken]

Homework Equations



KCL
KVL
V = IR

The Attempt at a Solution



I used 4 nodes at the top, one reference node at the bottom.

I have it labeled V1, V2, V3, V4, starting from the far left -> right.

My nodal equations are:

At v1:

+ 7V

At v2:

0 = (v2-v1) / 2 + v2 / 4 + (v2 - v3) / 4

At v3:

(v3-v2) / 4 + v3 / 8 + (v3 - v4) / 8 = 0

At v4:


0 = (v4-v3)/ 8 - 1mA

so we know V0 is v2-v3 = v0.

I'm not sure if this is correct so far.
 
Last edited by a moderator:

Answers and Replies

  • #2
mjsd
Homework Helper
726
3
your image is too small to be legible
 
  • #3
doodle
161
0
So far it's correct.

your image is too small to be legible

Try clicking on the (thumbprint) image to view a larger one.
 
  • #4
ravenprp
74
0
For v4, is it 8V in my case? I'm stuck with the simult. equations, and I'm just curious. I have a 1mA current going through the 8k resistor, so I'm believing its 8V? Can anyone verify this?
 
  • #5
ravenprp
74
0
I have simplified it to this:

V1 = 7V (like before)

for node at V2...

4V_2 - 2V_1 - V_3 = 0

for node at V3...

4V_3 - 2V_2 - V_4 = 0

for node at V4...

V_3 - V_4 = 8

So, all of the eq put together...

4V_2 - 2V_1 - V_3 = 0
4V_3 - 2V_2 - V_4 = 0
V_3 - V_4 = 8
V_0 = V_2 - V_3


I'm not sure what to do after here.
 
  • #6
doodle
161
0
For v4, is it 8V in my case? I'm stuck with the simult. equations, and I'm just curious. I have a 1mA current going through the 8k resistor, so I'm believing its 8V? Can anyone verify this?

No, v4 is not 8V, but either one of (v4-v3) or (v3-v4) is and it is not difficult to figure out which one is.

I have simplified it to this:

V1 = 7V (like before)

for node at V2...

4V_2 - 2V_1 - V_3 = 0

for node at V3...

4V_3 - 2V_2 - V_4 = 0

for node at V4...

V_3 - V_4 = 8

<snip>

I'm not sure what to do after here.

The nodal equation for node 4 is incorrect. Please check that against your first post. You have above 3 equations with 3 unknowns (v2, v3, v4). It becomes thus a mathematical problem now to resolve the 3 unknowns. The final step, of course, would be to put these values into finding v0 = v2-v3.
 
  • #7
ravenprp
74
0
Oh, woops, it should be v_4 - v_3 = 8, as in my first post.

Its this math part that kills me, I'll be back in a few:)

Thanks so far, doodle.
 
  • #8
ravenprp
74
0
Nevermind, it's correct. I just checked.

Thanks for all those that helped :)
 

Suggested for: Simple Nodal Analysis

  • Last Post
Replies
7
Views
270
Replies
22
Views
866
Replies
2
Views
227
Replies
2
Views
524
  • Last Post
Replies
5
Views
1K
Replies
4
Views
2K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
15
Views
831
Replies
1
Views
1K
  • Last Post
Replies
4
Views
1K
Top