Simple Optics: Image Formed By Two 15cm Lenses

  • Thread starter Thread starter beethoven'smahomeboy
  • Start date Start date
  • Tags Tags
    Optics
AI Thread Summary
An object placed 15 cm from a converging lens with a focal length of 15 cm results in an image formed at infinity. This occurs because the object is at the lens's focal point, causing parallel light rays to exit. The second lens, positioned 20 cm from the first and also with a focal length of 15 cm, treats the light from the first lens as coming from a distant object. Consequently, the second lens forms an image at its focal point, which is also at infinity. The final image remains the same size as the original object due to the equal focal lengths of both lenses.
beethoven'smahomeboy
Messages
5
Reaction score
0
An object is 15 cm from a converging lens of focal length 15 cm. A second positive lens of focal length 15 cm is 20 cm from the first lens. Where is the final image (s)?

Since 1/15+1/s=1/15 by the thin-lens equation, is there an image formed?
 
Physics news on Phys.org
beethoven'smahomeboy,
If light from a far away object (parallel light rays) falls on a convex lens it will form an image of the object in it's focal plane (that is how the focal length of such a lens is defined). If an object is placed at the focus of a lens we get conversely that it forms an image of the object at infinity (very far away) again with parallel light rays leaving the lens. Your equation above get 1/s as zero, which implies that the image is at infinity. For the second lens the light looks like it is coming from an far away object (that is the rays are traveling parallel to each other after leaving the first lens). This means that the second lens will form an image of the original object at it's second focus. The distance between the two lenses are irrelevant. The object is therefore mapped from the focal point of the first lens to that of the second lens. Since both lenses have the same focal length the final image will be the same size as the original.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are; Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction. Must be LESS than 1 kg. NO parachutes. NO glue or Tape can touch the egg. MUST be able to take egg out in less than 1 minute. Grade A large eggs will be used.
Back
Top