Solve a Simple Power Problem: Escalator Work Rate

  • Thread starter Thread starter pinky2468
  • Start date Start date
  • Tags Tags
    Power
AI Thread Summary
To solve the escalator work problem, first calculate the vertical height using the sine of the angle: height = 30m * sin(30°), which equals 15m. The work done in lifting the man is given by the formula W = mgh, where m is the mass (50kg), g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height calculated. Power can then be determined using P = W/t, where t is the time taken to ascend the escalator, calculated from the speed of 1.00 m/s and the length of the escalator. The key steps involve finding the height and using the correct formulas for work and power. Understanding these calculations will lead to the solution of the power required to lift the man.
pinky2468
Messages
86
Reaction score
0
I am not sure why I am stumped on this problem, but here it is

An escalator 30.0 meters long slants 30degrees relative to the horizontal. If it moves at 1.00m/s at what rate does it do work in lifting a 50kg man from the bottom to the top?

Any suggestions on where to start?
 
Physics news on Phys.org
work done in lifting is mgh, so power is time derivative: mg dh/dt. dh/dt is the vertical component of the velocity. Since you have the velocity magnitude and direction, you can figure out the vertical component.
 
What does the d stand for. Do I need to find the height by using sin 30?
 
I have a feeling you don't know calculus. d stands for derivative or change in. your formula for power is P= mgh/t all you have to do is figure out the height using sin30 with your length and your time with sin30 your speed.
 

Thread 'Rolling without slipping on a curved surface'

Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Negative vs Positive work on an escalator
Replies
8
Views
4K
How Much Power Does an Escalator Need to Operate Fully Laden?
Replies
8
Views
8K
Physics problem on power involving escalators
Replies
1
Views
3K
What is the work rate of an escalator lifting a woman from bottom to top?
Replies
2
Views
3K
A Physics 11 Elevator Work/Power Problem
Replies
3
Views
4K
How Do You Calculate Power in These Physics Problems?
Replies
5
Views
2K
How Long to Reach the Top Walking on a Moving Escalator?
Replies
4
Views
3K
Seeking advice on "simple" pendulum problem
Replies
27
Views
2K
Navigating Wind: Solving Plane and Escalator Problems
Replies
3
Views
3K
Solve Escalator Question Homework: Walk Up & Down Moving/Stalled Escalator
Replies
3
Views
8K

Hot Threads

Recent Insights

Back
Top