Engineering Simple question about KVL Equation in a BJT Circuit

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    Bjt Circuit Kvl
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The discussion focuses on deriving the KVL equation for a BJT circuit to find the base current (Ib). The initial equation presented is Vcc - IcRc - IbRb - Vbe = 0, but there is uncertainty regarding the voltage drop across Rc. It is clarified that the drop should be represented as IeRc instead of IcRc, emphasizing the relationship between the base current, collector current, and emitter current. Participants suggest adding the IbRc term to the equation for accuracy. The conversation highlights the importance of understanding current relationships in BJT circuits.
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Homework Statement



I am trying to find the KVL equation for this BJT in order to find Ib.
http://www.ece.auckland.ac.nz/oasis/a/att/qtatt/2028/2/261/IM010


Homework Equations





The Attempt at a Solution



My current equation looks like this.
Vcc - IcRc - IbRb - Vbe = 0

I am not entirely sure if this is correct.
 
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1. Is the drop across Rc really just IcRc? (Hint: you're close, but no cigars).
2. More importantly, what is the relationship between Ib and Ic for a BJT?
 
rude man said:
1. Is the drop across Rc really just IcRc? (Hint: you're close, but no cigars).
2. More importantly, what is the relationship between Ib and Ic for a BJT?

I just thought about it.
The base current and collector current equals to the emitter current.

So, the drop across the Rc is actually IeRc?
 
Yes. Add the IbRc term to your original equation, don't use Ie.

Now for part 2?
 

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