shadowmystic9
- 1
- 0
(Simple) Vector Problem..don't see what I'm doing wrong!
If the vector B is added to vector C = 3.7 i + 4.9 j , the result is a vector in the positive direction of the y axis, with a magnitude equal to that of C. What is the magnitude of B?
Here is what I did -
Magnitude is r = sq rt of Ax^2 + Ay^2 components
therefore, the magnitude of C is
3.7^2 + 4.9^2, take sq rt = 6.14 = magnitude of C
The question is for the magnitude of B. The resultant vector, according to the problem, has the same mag as C, so I would use the Pythagorean theorem =
A^2 + b^2 = C^2
6.14 ^2 + 6.14 ^2 = 75.3992, take sq rt = 8.68.
However this answer is not correct. I do not see where I went wrong, please help. Thank you!
Homework Statement
If the vector B is added to vector C = 3.7 i + 4.9 j , the result is a vector in the positive direction of the y axis, with a magnitude equal to that of C. What is the magnitude of B?
Here is what I did -
Magnitude is r = sq rt of Ax^2 + Ay^2 components
therefore, the magnitude of C is
3.7^2 + 4.9^2, take sq rt = 6.14 = magnitude of C
The question is for the magnitude of B. The resultant vector, according to the problem, has the same mag as C, so I would use the Pythagorean theorem =
A^2 + b^2 = C^2
6.14 ^2 + 6.14 ^2 = 75.3992, take sq rt = 8.68.
However this answer is not correct. I do not see where I went wrong, please help. Thank you!