1. The problem statement, all variables and given/known data A one-dimensional force acts on a particle of mass m = 6.26 kg in such a way that its position is given by: x = 0.484t^3 - 33.6t Find W, the work done by this force during the first 1.49 s. 2. Relevant equations W=F*s W=mgs Integration 3. The attempt at a solution I just wanted to know whether I'm solving this correctly because I only have one more chance to input an answer in my online homework system (as those of you who have been helping me probably know by now. Anyhow, this is what I've done. W=Fs F=mg W=mgs **Because the position is variable but the mass and gravity are constant, we integrate the formula given, and we get: W=mg*∫x.dx= (.121t^4) - 16.8(t^2), from 0s to 1.49s We come to: W=mg*(-36.7) W=6.26*9.81*(-36.7)= (-2253.8) J Did I do this properly?