Simplify to find theta, my brain is fuzzled from to much work today

smell5
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2(exponential^theta)^2 - 10 = 6(exponential ^theta)
 
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It's a simple quadratic equation a*x^2 + b*x + c = 0 , where x = e^theta.
You can do it, don't give up. ;)
 
Quadratic too.
 
Could it not be set up as 2e^(2x)-6e^x = 10?
 
Just a gentle reminder to homework helpers: we help people do their problem, rather than doing the problem (or all of the thinking) for him.

If he's too fuzzled to work on the problem, then he needs to wait until he can clear his head and start on the problem himself before he can post here.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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