Simplifying a Double Integral: No Known Anti-Derivative

CharmedQuark
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Homework Statement



The equation is \int^{t}_{0}e^{-t'\gamma}\int^{t}_{0}e^{t''\gamma}f(t'')dt''dt'. f(t) is a random function with no known anti-derivative. I need to simplify this into a single integral of one variable.

Homework Equations


above.

The Attempt at a Solution


I moved the first exponential function inside the second integral but none of the regular properties of double integrals seem to work here. Does anyone have any ideas?
 
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As written you have simply the product of two integrals,

\left[\int^{t}_{0}e^{t&#039;\gamma}dt&#039; \right]<br /> \left[ \int^{t}_{0}e^{t&#039;&#039;\gamma}f(t&#039;&#039;)dt&#039;&#039;\right]

and the first one is simple.
 
No, It's not a typo. I had no idea that that could be done. Thank you this makes this a lot easier.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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