Sin t = a+b, cos t = a-b, find tan t

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The problem involves finding tan theta given the equations sin theta = a + b and cos theta = a - b, with the condition that a/b = 3. The solution is derived by expressing tan theta as the ratio of sin theta to cos theta, resulting in tan theta = (a + b) / (a - b). Substituting a = 3b into the equation leads to the final answer of tan theta = 2. The discussion confirms that the problem is solvable and provides the correct answer.
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Homework Statement


Im wondering if this question could be solved.

Given that sin theta =a+b and cos theta =a-b

Find tan theta when a/b=3

Solved alr.. the ans is 2.

Homework Equations


The Attempt at a Solution

 
Last edited:
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icystrike said:

Homework Statement


Im wondering if this question could be solved.

Given that sin theta =a+b and cos theta =a-b

Find tan theta when a/b=3

Homework Equations





The Attempt at a Solution


sinθ=a+b
cosθ=a-b

sinθ / cosθ = a+b / a-b

I think, now you can continue. Regards.
 

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