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Sinh in Snell's Law?

  1. Oct 21, 2013 #1
    "sinh" in Snell's Law?

    1. The problem statement, all variables and given/known data

    I'm trying to understand some equations in my AS level textbook about Snell's Law

    2. Relevant equations

    The equations are in the image below

    3. The attempt at a solution

    I tried reading up about sinh but I don't fully understand what it is. Also I'm not sure what the term beside sinh is. It can't be a "1" and to seems like a small letter L which comes out of nowhere?

    image.png
     
  2. jcsd
  3. Oct 21, 2013 #2

    DrClaude

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    Staff: Mentor

    That looks like a typesetting problem. The greek letter θ corresponds to the roman letter q (try typing q in a font like Symbol). I'm not sure where the big 1 comes from, but it should be a μ. Then you recover Snell's law:
    $$
    \mu_1 \sin \theta_1 = \mu_2 \sin \theta_2
    $$
     
  4. Oct 21, 2013 #3

    gneill

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    Staff: Mentor

    I have seen a version of Snell's law where there is not just refraction taking place but also energy absorption and reflection at interfaces. They used complex indexes of refraction and complex angles! Hyperbolic sines replaced the sin() functions. Sorry I don't remember the reference, it was a good many years ago!
     
  5. Oct 22, 2013 #4

    ehild

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    Homework Helper
    Gold Member

    Snell's Law is equivalent to the continuity of the tangential component of the wave vector at an interface: The component of the wave vector k parallel to the surface is the same in both media. In case of an absorbing medium, k is complex. Representing the parallel component with ksinθ, Snells Law states that k1sinθ1=k2sinθ2.
    If the light came from a non-absorbing medium, k1 and θ1 are real. If k2 is complex, θ2 is a complex angle, and you have the complex sine function, ##\sin(z)=\frac{\exp(iz)-\exp(-iz)}{2i}=-i \sinh(iz)## But you can avoid by computing with complex angles if you use Snell's Law in the form kparallel= ko sinθo.

    ehild
     
    Last edited: Oct 22, 2013
  6. Oct 22, 2013 #5

    DrClaude

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    Staff: Mentor

    From the material presented in the OP, it is clear that this is introductory level. Hyperbolic sines have nothing to do with the poster's question, and the equation doesn't make mathematical sense (in terms of notation) if one interprets sinh as a hyperbolic sine.
     
  7. Oct 22, 2013 #6

    vanhees71

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    2016 Award

    Well, never trust texts that are written with M$ Word or similar pseudo-typesetting programs. There are exceptions, but usually one has to be very careful with such texts:devil:.
     
  8. Oct 22, 2013 #7
    Hmm...

    Yup, this is intro level physics and I have to agree with DrClaude: This is just one weird typesetting error. Thanks for the help guys.
     
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