(sinθ/(1-cotθ)) + (cosθ/(1-tanθ)) = cosθ + sinθ

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AI Thread Summary
The discussion centers on proving the equation (sinθ/(1-cotθ)) + (cosθ/(1-tanθ)) = cosθ + sinθ. A participant shares their near-complete solution but expresses frustration over a mistake related to the difference of squares. Another member offers constructive feedback, suggesting improvements for posting images of work, emphasizing clarity and appropriate sizing. The conversation highlights the collaborative nature of solving mathematical problems and the importance of clear communication in sharing solutions. Overall, the thread showcases the process of tackling a trigonometric proof while encouraging better presentation of work.
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Homework Statement


I have to prove that:

(sinθ/(1-cotθ)) + (cosθ/(1-tanθ)) = cosθ + sinθ


Homework Equations





The Attempt at a Solution


Here's my attempt at solution...
6gy26c.jpg

 
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Very close!
a2 - b2 = ?
 
OMG how unbelievably stupid of me...
obviously (a - b)(a + b)

thanks a lot bro... :D
 
th4450,
If you post a photo of your work in another thread,
1) Take a better picture. This one was so dark it was barely legible.
2) Shrink the image so that it is no larger than 800 x 600 pixels.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...

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