Siren Wavelength for Car Travelling North at 29.4 m/s

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SUMMARY

The discussion focuses on calculating the wavelength of sound from an ambulance's siren as it approaches a car traveling North at 29.4 m/s. The ambulance travels at 64.1 m/s, and the frequency of the siren is 705 cycles/s. Using the formula wavelength = velocity / frequency, the wavelength at the car driver's position is determined to be 0.486 meters. This calculation highlights the impact of the Doppler effect, which causes the wavelength to decrease and the frequency to increase as the ambulance approaches, resulting in a higher pitch perceived by the car driver.

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An ambulance is traveling North at 64.1 m/s, approaching a car that is also traveling North at 29.4 m/s. The ambulance driver hears his siren at a frequency of 705 cycles/s. The velocity of sound is 343 m/s. What is the wavelength at the car driver's position for the sound from the ambulance's siren? Answer in units of m.
 
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Do you know those 4 cases (actually only one useful in this problem) of Doppler effect...?Which case of the 4 does this problem correspond to?

You should always review the theory first?

Daniel.
 


The wavelength at the car driver's position for the sound from the ambulance's siren can be calculated using the formula: wavelength = velocity / frequency. In this case, the velocity of sound is given as 343 m/s and the frequency is 705 cycles/s. Therefore, the wavelength can be calculated as:

wavelength = 343 m/s / 705 cycles/s = 0.486 m

This means that the sound waves from the ambulance's siren have a wavelength of 0.486 meters at the car driver's position. This is important to note because as the ambulance approaches the car, the wavelength of the sound waves will decrease due to the Doppler effect. This will result in a higher frequency and a higher pitch of the siren as perceived by the car driver. It is important for drivers to be aware of this effect and adjust their driving accordingly to avoid potential accidents.
 

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