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Sketching Solution

  1. Jan 10, 2009 #1
    1. Question: Sketch the solution to

    absolutevalueof*(w-2j) = 3

    now if i had this type of question

    absolute(x-3) = 4

    i would go

    x-3 if x greater than 3
    -(x-3) if x less than 3
    and solve separately

    x = 7 and x = -1

    Now should i do the same approach to this question Im a little confused :(

    (w-2j) if w is greater than 2j
    -(w-2j) if w is less than 2j

    w = 3 + 2j


    w = -3 + 2j

    are those the only two solutions ?

    and if so how do i sketch them ?

    should I just make an imaginary and real axis and draw two `vectors` with the above components....
  2. jcsd
  3. Jan 10, 2009 #2
    or actually i just noticed that absolute value is probably the magnitude of that complex number.....hmmmm

    thats weird should how I approach that then :S
  4. Jan 12, 2009 #3


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    The difference of two numbers a - b, is a vector from b to a. The absolute value is the distance. What is the locus of the points that are at a distance 3 for the point 2j?
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