Solve a Skier Work Physics Problem on a 37.2° Slope – No Friction

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To calculate the work required to pull a skier up a frictionless slope, the focus should be on gravitational potential energy rather than kinetic energy. The relevant equation is U = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height gained. Since the skier is moving at a constant speed, the work done does not contribute to changing kinetic energy but instead increases gravitational potential energy. Therefore, the work done is equal to the change in potential energy as the skier ascends the slope. Understanding these principles is crucial for solving the problem accurately.
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A skier of mass 72.6 kg is pulled up a slope by a motor-driven cable. How much work is required to pull the skier 64.3 m up a 37.2 degrees slope? (assumed frictionless) at constant speed of 63.2 m/s.

For this question, would I just use the equation W = 1/2 mv squared?

Thank you so much!
 
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it is gaining height too, so PE=mgh is needed too
 
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shramana said:
The velocity is not constant here.
I would use W=f.d
"...at constant speed of 63.2 m/s."

No--the equation K = (1/2)mv^2 is for kinetic energy. In your problem, the skier's kinetic energy remains the same because his speed remains the same. Only his gravitational potential energy (U = mgh) changes. Since the work done pulling the skier up does not go to changing his kinetic energy, it must have gone to changing his gravitational potential energy, right?
 
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Oh I see! Thank you very much for your help!
 
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