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mortho
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[SOLVED] Skier's coefficient of velocity
A skier traveling 12.0 m/s reaches the foot of a steady upward 18° incline and glides 14.2 m up along this slope before coming to rest. What was the average coefficient of friction?
Wnet=delta KE
coefficient=Ff/Fn
and a ton of other Forces equations
This problem was amazingly hard..so many steps but here's what i did
Wnet=delta KE
Fnetd=Delta KE
Fa-(Ff+Fp)d=1/2mv2
Fa-(coefficient Fn+ Fp)d=1/2 mv2
Fa- (coefficient Cos 18 g + Sin 18 g)d=1/2mv2
Finally i got my answers which came up to 18.7 is that right?
and also i couldn't figure out how to get Fa so i didn't even put in anything for that in my calculations , so i know it's wrong. Thanks for your help
Homework Statement
A skier traveling 12.0 m/s reaches the foot of a steady upward 18° incline and glides 14.2 m up along this slope before coming to rest. What was the average coefficient of friction?
Homework Equations
Wnet=delta KE
coefficient=Ff/Fn
and a ton of other Forces equations
The Attempt at a Solution
This problem was amazingly hard..so many steps but here's what i did
Wnet=delta KE
Fnetd=Delta KE
Fa-(Ff+Fp)d=1/2mv2
Fa-(coefficient Fn+ Fp)d=1/2 mv2
Fa- (coefficient Cos 18 g + Sin 18 g)d=1/2mv2
Finally i got my answers which came up to 18.7 is that right?
and also i couldn't figure out how to get Fa so i didn't even put in anything for that in my calculations , so i know it's wrong. Thanks for your help