Smoothing effect of full wave rectification

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SUMMARY

The discussion focuses on the smoothing effect of full wave rectification using capacitors and resistors. A single capacitor is connected across a resistor in a diode bridge setup, and the user inquires about the impact of increasing the resistance instead of adding a second capacitor in parallel. It is established that increasing the resistance affects the load current drawn from the capacitor, which in turn influences the voltage stability across the capacitor. The conclusion is that while increasing resistance can improve smoothing, it does not replicate the effect of adding a second capacitor in parallel.

PREREQUISITES
  • Understanding of full wave rectification circuits
  • Knowledge of capacitor behavior in electrical circuits
  • Familiarity with resistor-capacitor (RC) time constants
  • Basic principles of load current in electrical systems
NEXT STEPS
  • Research the effects of capacitor sizing on smoothing in rectifier circuits
  • Study the relationship between load resistance and capacitor discharge rates
  • Explore the use of multiple capacitors in parallel for improved voltage stability
  • Learn about RC time constant calculations in smoothing applications
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Electrical engineering students, circuit designers, and hobbyists interested in improving the performance of rectifier circuits through effective smoothing techniques.

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Homework Statement


Hi,

I have this question regarding to the smoothing effect of full wave rectification. In order to smooth out the wave. A capacitor is added across a resistor which is connect across a diode bridge. In order to increase the smoothing effect 2nd capacitor can be added across the resistor. So it means that are two parallel capacitor connected across the resistor. My question is instead of adding the 2nd capacitor to the resistor. How if i increase the resistance of the resistor (connected parallel with the 1st capacitor only)? would this also increase the smoothing effect as similar as two capacitor in parallel connected across a resistor?

Any one can help me? I can't find the answer to this question!


Homework Equations




The Attempt at a Solution

 
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As you describe it the resistor is acting as the load on the rectifier setup. When the rectifier input voltage drops below the current voltage held on the capacitor, where is the load drawing its current from? What happens to the voltage on the capacitor? What if you change the amount of current being drawn by the load (by changing the load resistance)?
 

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