Snells Law and a triangle prism

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A light ray entering a right-angle prism at a right angle splits into two rays upon emerging, diverging at 8.5 degrees. The prism's angles are 32 degrees and 58 degrees, with the initial ray striking at 70 degrees relative to the normal. The first ray exits at 12 degrees lower than the incident angle, leading to calculations for the index of refraction for each wavelength. The discussion suggests using Snell's Law to determine the indices, with air's index set at 1. A diagram is requested for clarity in visualizing the angles and refraction.
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A light ray in air strikes the flat side of a right angle prism at a right angle. The prism has 32 58 as the other angles with 32 degrees being in the bottom and the right angle being to the right of it. The light ray consist of two different wavelenghts. When it emerges at the face AB. It was been split into two different rays that diverge from each other at 8.5 degrees. The first ray is 12 degrees lower then when the initial ray strikes the prism

Find the index of refraction of the prism for each of the two wavelenghts?

nsintheta=nsintheta


since air is 1 is it just

sin70/sin 58

and

sin78.5/sin58
 
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A diagram would be nice.
 

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