So you'd use the top loop and the right-hand loop.

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The discussion focuses on solving a circuit problem involving three currents (i1, i2, i3) and the development of three equations based on the circuit's loops and junctions. The participant initially presents their equations, but there is confusion regarding the correct formulation of the third equation, which is clarified by others in the thread. It is emphasized that two loop equations and one junction equation are necessary to solve the circuit, with a suggestion to choose the simplest loops for ease of calculation. The importance of correctly identifying the direction of currents in relation to the resistors is also highlighted. The conversation concludes with confirmation that the outer loop equation is correctly formulated.
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Homework Statement



http://img251.imageshack.us/img251/3123/photo2152.jpg

Homework Equations



i don't know of any..

The Attempt at a Solution



Ok, so the professor told us to develop three equations, but to only use two of those to try and solve for the currents, i1, i2, i3.

All i know is the currents coming in are equal to the ones coming out.

So, I probably have these wrong, but here are the equations so far.

1) I2 + I3 = I1
2) -I3R3 - V2 - I1R1 + V1 = 0
3) -I3R3 - V2 - I1R1 + V1 = 0


are these wrong? help me get them right, I am so lost.
 
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Hi Princess19! :smile:

(try using the X2 icon just above the Reply box :wink:)

Your 1) and 2) look right :smile:

but you've copied your 3) wrong, it's the same as 2) ! :redface:

btw, I think you've misunderstood your professor …
Princess19 said:
Ok, so the professor told us to develop three equations, but to only use two of those to try and solve for the currents, i1, i2, i3.

… this circuit has 2 loops, so you do need 3 equations to solve it: one junction and 2 loop equations

I think your professor meant that there are 3 loop equations (left loop right loop and outer loop), but you only need 2 of them (because they're linearly dependent), plus a junction loop, making 3 …

and he wants you to write all three loop equations, but then use only 2 of them :wink:
 
oops! would this be equation 3?

i3R3 - i2R2 + V2 = 0
 
Hi Princess19! :smile:
Princess19 said:
oops! would this be equation 3?

i3R3 - i2R2 + V2 = 0

he he! :biggrin:

Yes, that looks good :smile:

now solve!​

(btw, you still haven't given the third loop equation. :wink:)
 
is the first equation a loop equation?

i have no idea about the third loop equation. can you give me some sort of hint to get started on?
 
The first equation is a junction equation (i'm not sure that's the official name, but it's what I call it :wink:).

The 3rd loop equation is for the outside loop, ie the one with V1 R1 and R2.
 
would equation 3 be i3R3 - i2R2 + V2 = 0 or -i3R3 - i2R2 + V2 = 0


okay, how about this for the outer loop

V1 - I2R2 - I1R1 = 0
 
Hi Princess19! :smile:

(just got up :zzz: …)
Princess19 said:
would equation 3 be i3R3 - i2R2 + V2 = 0 or -i3R3 - i2R2 + V2 = 0

You're marking I3 as going down the page, ie anti-clockwise in that loop, and I2 as clockwise, so they must be opposites, so it's the first one (which you had originally, in post 3 :wink:).

Personal grouch: I don't like professors who tell you to draw those circular arrows … I think it's much safer to draw arrows directly on the lines themselves … then you can easily see which currents are going the "wrong way" through any resistor, and how they add up at each junction.​

okay, how about this for the outer loop

V1 - I2R2 - I1R1 = 0

Yes, that's right. :smile:

Note that this loop equation is the sum of the other two loop equations, so it gives no new information

that's what your professor meant about only needing to use two of the loop equations!

In practice, you take a quick look at the diagram, and choose the two loops that look simplest …

in this case, I'd leave out the left-hand loop, because it has 4 items in it, while the other two loops have only 3. :wink:
 
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