Soccer ball rebouncing of the goal post

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A 420 g soccer ball traveling at 23 m/s strikes a goal post and rebounds at 18 m/s, with contact lasting 3.3 ms. The initial calculation for average acceleration yielded -1515.15 m/s², but it was noted that the time of contact shouldn't be used for the entire motion. The correct approach involves calculating the change in velocity, considering the direction change, resulting in an acceleration of approximately 12,121.21 m/s². The discussion emphasizes that the impulsive force during the impact leads to a very high acceleration value. Understanding the dynamics of the collision is crucial for accurate calculations.
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Homework Statement


A 420 g soccer ball traveling at 23 m/s hits the goal post and rebounds at 18 m/s. If the ball is in contact with the post for 3.3 ms, what is the average acceleration of the ball during this time interval?

Homework Equations


Here I used 23m/s as initial velocity v_i and 18m/s as the final velocity v_f, and t = 0.0033s as the time traveled.

The Attempt at a Solution


I used a_x = v_f - v_i / t, so 18-23/0.0033 which gave me -1515.15m/s^2, which in my opinion seems to be a whole lot. Then I noticed that I can't use the goal post contact time as time traveled. So I am trying to find the time the ball actually traveled from start to hit the post and from rebound to the stop of the ball. Given those values I am stuck finding out how to get the time.
 
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Ah..you made a mistake..a=change in velocity/time taken
the direction of ball changes after rebound so change in velocity=(18-(-23))
And acceleration=(40)/0.0033
and also don't worry about the magnitude of acceleration.The force acting on the soccer will be impulsive(have very large value) so the acceleration will also be very high
 
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