Solenoid force to electrical current

AI Thread Summary
The discussion focuses on the relationship between mechanical force and electrical current in solenoids. Key factors influencing the force produced include the number of wire turns, solenoid size, and the magnetic properties of the materials used. A specific example is given where a solenoid driver circuit is designed to hold 2 lbs of force, highlighting the complexity of calculating the required power or current. Additionally, comparisons are made between different solenoids, illustrating the wide range of force outputs based on design and application. Understanding these variables is crucial for effectively designing solenoid systems.
Mike Phan
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Hi,

Please remind me of formulas to convert the mechanical froce (lb) to electrical current (I) or power (W)? Thanks

Mike
 
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That sounds a bit strange to me. The force should depend just as much upon the number and arrangement of windings, and also the material that the plunger is made of. :confused:
 
I meant, if we design a solenoid driver ckt that can hold 2 lb (force), what power or current minimum needed to do this job.
 
As Danger indicated, the amount of force created is not only related to the amount of electrical current applied, but also to other factors such as the number of turns of wire in the coil, the size of the solenoid, and the magnetic character of the steel used will affect the amount of force developed.

Is the force of 2 lbs on the core?
 
As a 'for instance', some 115 VAC appliances have solenoids which barely put out an ounce of force, such as the hold-down latch in a toaster. Conversely, EftonScience (formerly Edmund Scientific Co.) sells one that runs on two 'D' size batteries and can lift 500 lbs.
 
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