Solution check for a Rate problem

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The discussion revolves around calculating the rate at which the mass of candies in a vertical container increases, given specific dimensions and properties of the candies. The container's base area is 238 cm², and each candy has a volume of 50 mm³ and a mass of 0.0200 g. The height of the candies increases at a rate of 0.250 cm/s, leading to a need for determining the mass increase rate in kilograms per minute. Participants confirm the method used is generally correct, although one contributor mistakenly included unnecessary calculations related to the volume of a sphere. The conclusion emphasizes that the negligible space between candies simplifies the problem, negating the need for additional dimensions.
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Homework Statement


A vertical container with base area measuring 14.0 cm by 17.0 cm is being filled with identical pieces of candy, each with a volume of 50.0##mm^3## and a mass of 0.0200 g. Assume that the volume of the empty spaces between the candies is negligible. If the height of the candies in the container increases at the rate of 0.250 cm/s, at what rate (kilograms per minute) does the mass of the candies in the container increase?

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The Attempt at a Solution


Please see attached image to see my work and drawings. My solution is boxed in the bottom, but the text doesn't have a solution to this problem so I'm unsure if it's correct or not.
 

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opus said:

Homework Statement


A vertical container with base area measuring 14.0 cm by 17.0 cm is being filled witqh identical pieces of candy, each with a volume of 50.0##mm^3## and a mass of 0.0200 g. Assume that the volume of the empty spaces between the candies is negligible. If the height of the candies in the container increases at the rate of 0.250 cm/s, at what rate (kilograms per minute) does the mass of the candies in the container increase?
Why does ##\pi## appear in your solution?

AM
 
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I didn't check the arithmetic operations but your method looks correct to me. We are not given whether each candy is spherical, but we are given that the space between the candies is negligible and I think that's enough.
 
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Andrew Mason said:
Why does ##\pi## appear in your solution?

AM
That was unnecessary information that I came up with, but the reason it's there is because I used the volume of a sphere formula to get the radius and the diameter of each candy but I ended up not needing those.
 
Delta2 said:
I didn't check the arithmetic operations but your method looks correct to me. We are not given whether each candy is spherical, but we are given that the space between the candies is negligible and I think that's enough.
Ok that's all I needed to know- if the method was correct or not. I was initially under the impression that I'd need to find the diameter of each candy to see how many I could fit in the base laying flat but that seemed not needed. Thank you.
 
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