Solve Absolute Values: z∈C |z - 1| = 5, |z - 4| = 4, |4 - z2| = z

AI Thread Summary
The discussion revolves around solving two complex number equations involving absolute values. For the first equation, the user successfully determined that z = 4 ± 4i is correct. In the second equation, they initially struggled but realized that z must be a real number, leading to insights about defining absolute values. Ultimately, they found the solutions to be positive roots, specifically ±(1 + √17)/2. The conversation emphasizes the importance of considering the nature of absolute values in complex equations.
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Homework Statement


So I've got two problems I'm struggling a bit with. One of them I've solved (I think), but I'm definitely not sure. The other one is bugging me a bit. Anyway:

i] Determine all z∈C so that |z - 1| = 5 and |z - 4| = 4

ii] Determine all z∈C so that |4 - z2| = z


Homework Equations





The Attempt at a Solution


i] I say that z = x+yi as a starting point. From there:

|x + yi -1| = 5
√( (x - 1)2 + y2 ) = 5
x2 + 1 -2x +y2 = 25

|x + yi -4| = 4
√( (x-4)2 + y2 ) = 4
x2 + 16 - 8x + y2 = 16

y2 = 8x - x2

Inserting this in the first equation:

x2 + 1 - 2x + 8x - x2 = 25

6x + 1 = 25

x = 4

and then y2 = 32 - 16 = 16, y = ± 4

So I get z = 4±4i

I think this should be correct, but I'm a bit.. unsure.


ii] I've gotten so far that I've looked at the exercise and realized that the absolute value of something is always a real number, which means if z = x+yi, then y=0. But from here I'm unsure on how to proceed.

How on Earth am I supposed to solve this? I'm feeling.. lost.
 
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i] is correct.

ii] You are right, z is real. How do you define the absolute value of a real number?

ehild
 
The only thing I can think of right now (it's.. late) is:

|x| = x if x>0
|x| = 0 if x=0
|x| = -x if x<0

Is this what you mean?
 
Never mind, I had a insight today during my lecture and suddenly it was all very, very clear and the answers are something like ±(1 + √17)/2

Thanks though!
 
Almost good! Do not forget that z can not be negative as it is equal to an absolute value. You had two second order equations, with 4 roots altogether, but only the positive roots are valid. (±1 + √17)/2

ehild
 
Yeah, sorry, I put the plus/minus sign wrong :) I figured that out and even checked if they were in the right intervals and such.
 
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