Solve Box on an Incline with Trig, Geom & Newtons Laws

  • Thread starter Thread starter Ainulph
  • Start date Start date
  • Tags Tags
    Box Incline
AI Thread Summary
The discussion focuses on solving a physics problem involving a box on an incline using trigonometry, geometry, and Newton's laws. The user expresses confusion about applying Cartesian coordinates to the incline and understanding the normal force in relation to gravity's components. They note the importance of dividing the applied force into its x and y components, specifically mentioning the normal force. A participant corrects a misunderstanding regarding the calculation of the normal component. The conversation highlights the complexities of analyzing forces on an inclined plane.
Ainulph
Messages
4
Reaction score
0

Homework Statement


RjsIC.jpg



Homework Equations


Trigonometry
Geometry - Intersection on a Line
Physics - Newtons Laws


The Attempt at a Solution


rtcI6.jpg

I am just lost. I move the Cartesian coordinates to the incline of the free body diagram to begin.I know that the normal force is perpendicular to the surface and that the force of gravity must be divided into its x and y components. Considering Newton's Third Law, the force applied to the incline by the gravity and person should equal to normal force that box experiences.

Thanks for reading, hope to hear by you soon.
 
Physics news on Phys.org
Divide also the applied force into its x (parallel to the slope) and y (normal to the slope) components. The normal component is not 110/tan(64°).

ehild
 
Ah, thank you! I can't believe I made that mistake every time.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top