Solve Conics Hyperbola Homework Statement

  • Thread starter Thread starter Mentallic
  • Start date Start date
  • Tags Tags
    Conics Hyperbola
Mentallic
Homework Helper
Messages
3,802
Reaction score
95

Homework Statement


http://img11.imageshack.us/img11/6340/conicshyperbola1.jpg

Homework Equations


d^2=(x_2-x_1)^2+(y_2-y_1)^2

y-y_1=m(x-x_1)

m_1m_2=-1


The Attempt at a Solution


I was able to answer (i) but for (ii) I would go about it like this:

Find the equation of the line SR by using that it is perpendicular to the line l and passing through the focus S(ae,0). Then solve both equations simultaneously to find the point of intersection at R(x,y). Then find the distance between S and R given that I know both coordinates.
But looking at the marking criteria, it is only worth 1 mark and thus must have a much simpler way of being solved. Any ideas?
 
Last edited by a moderator:
Physics news on Phys.org
The only other thing I can see is to let point Q be the x-intercept of the line l and let R=(x,y). Then you can apply the Pythagorean Theorem to triangle QRS and solve for (x,y). The nice thing about this is that both points Q and S have only one nonzero coordinate.
 
Well then Q(acos\theta,0) but the problem with that technique is that I'll still need to use the distance formula after finding point R, which is basically not any faster than what my original thinking was.

I asked my teacher on this one, there is a basic formula that I completely forgot existed.

d=\frac{|ax_1+by_1+c|}{\sqrt{a^2+b^2}}

gives the perpendicular distance from a point to a line.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top