Solve Crate Pressure w/ Mass: 2.50x10^3 Pa

[jefgreen]

Homework Statement

A crate, whose bottom surface is 50.4 cm by 28.3 cm, exerts a pressure of 2.50x10^3 Pa on the floor. What is the mass of the crate.

Homework Equations

P=F/A
m=weight/gravity (9.80)

The Attempt at a Solution

2.50x10^3 F
------------=----------------
1 1.4x10^3 cm^2


F=3.5x10^6

m=weight/9.80

m=3.5x10^6
-----------
9.80


Answer: 3.6x10^5 kg

I feel as though I made a mistake somewhere...

 

[rl.bhat]

You have convert the length and the width from cm to meter.

 

[jefgreen]

so I would multiply 2.50x20^3 by .787 (.283m+.504m)?

 

[rl.bhat]

so I would multiply 2.50x20^3 by .787 (.283m+.504m)?

What is the formula for area?

.787 (.283m+.504m)
What is this?

 

[jefgreen]

What is the formula for area?

.787 (.283m+.504m)
What is this?

lxw?

 

[jefgreen]

A=lxw

So.. (.283m x .504m)= 0.119952. I am not sure about the units, but is this the correct answer?

 

[jefgreen]

would it be meters squared (m^2)?

 

[rl.bhat]

A=lxw

So.. (.283m x .504m)= 0.119952. I am not sure about the units, but is this the correct answer?

Now it is correct. Unit of the area is m^2.
Now F = P*A = ...?

 

[jefgreen]

F=299.88N

so...

m=weight/9.80

therefore m=299.88N/9.80 m/s^2

mass equals... 30.6kg

Correct?

 

[rl.bhat]

Correct.