Solve Engineering Problem: Air Flow Speed in Duct for 3x4.5x6m Room

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To solve the air flow speed problem in a room measuring 3.0 m by 4.5 m by 6.0 m, the total volume of the room must be calculated and replaced every 12 minutes. The volumetric flow rate (Q) can be determined using the formula Q = V * A, where V is the mean velocity and A is the cross-sectional area of the duct. The duct has a diameter of 0.30 m, allowing for the calculation of its area. By rearranging the formula to V = Q/A, the necessary flow speed can be derived after computing both Q and A. Understanding these calculations is essential for determining the required air flow speed in the duct.
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Pls help on this problem that I can not solve it.

a room measures 3.0 m by 4.5 m by 6.0 m. The heating and air conditioning ducts to and from the room are circular with diameter 0.30 m, and the air in the room is to be exchanged every 12 minutes. What is the necessary flow speed in the duct? ( Assume that the density of the air is constant)

thanks
 
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Please do not post homework problems in the tutorial section.

Basically, the is a volumetric flow rate problem. One knows the total volume of the room (L * W * H) which has to be replaced in 12 minutes or 720 s.

One knows the diameter of the duct work, so one computes the area.

Q = V * A, where Q = volumetric flowrate, V = mean velocity, and A = cross-sectional area.
 
Thanks

Thank for reply, Astronuc, I have a question, you said Q=V*A, V=velocity, but in the problem, it does not give velocity value, how do I get it. Thanks again.
 
V = Q/A, and one must compute Q and A to get V.
 
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