Solve Equations of Motion: Wrench Falling Past Window

AI Thread Summary
A workman drops a wrench, which takes 0.6 seconds to fall past a 2-meter tall window. To calculate the wrench's initial velocity as it reaches the top of the window, the equation of motion s = ut + 0.5at² is used, where acceleration due to gravity (g) is considered. The initial calculation yields an initial velocity of 6.27 m/s, but concerns about sign conventions arise, leading to a revised answer of -0.39 m/s. It's emphasized that specifying units is crucial in physics calculations to avoid losing points on assignments. Clear communication of direction and units is essential for accurate problem-solving.
Hurr1cane
Messages
11
Reaction score
0
Warning! Posting template must be used for homework questions.
Hey guys, I'm wondering if I can get some help with a question in my homework. Here's the question:

A workman on the scaffolding outside one of the physics classrooms drops a wrench. A pupil decides to time how long it takes for it to pass the classroom window. It was found that it took 0.6seconds to fall past the 2 metre tall window. Calculate the wrenches initial velocity as it appears at the top of the window.


I am presuming that this requires an equation of motion, but I am really not sure on where to start/what equation to use.

Any help would be greatly appreciated.
 
Physics news on Phys.org
Try writing down

a) The equations of motion you know.
b) What you know from the problem using the same variable names. Do you know the acceleration? Initial velocity? Final Velocity? Time? Distance?

Then have a go at choosing an appropriate equation. Post your choice and working and someone will let you know if that's right/wrong etc
 
Okay, thanks for the reply! Here's what I've done:

I rearranged s=ut+0.5at^2, so that I could find u. ( u= (s-0.5at^2)/t)

So, when I substitute in the values, I get:
u=(2-0.5x-9.8x0.6^2)/0.6, which gave me an answer of 6.27m/s.

I'm not too confident on whether this is correct or not though.
 
Need to be careful with the signs. Which way are you measuring s and u? Is up positive or negative? What about g?
 
For me, up is positive, and down is negative. Also, I wasn't aware that g was involved for that equation, aside from being used for the acceleration. Have I made a stupid mistake?
 
If up is positive, what signs should you have for the distance traveled and the initial velocity?
 
They should be negative! Okay, I get it now! Thanks for the help guys!

So, the answer will be -0.39?
 
That's what I get.

Remember that an examiner may not define the same direction as +ve so always state that early in your working.
 
Hurr1cane said:
So, the answer will be -0.39?

One very important thing: -0.39 what? A velocity is a dimensionful quantity and if you do not specify the unit we do not a priori know if it is m/s, km/h, km/s, or parsec/Hubble time.

I do not know about your teacher, but I typically make significant deductions of points if units are missing.
 
Back
Top