Solve for f: gradf = (2xy + sin(x)i + (x2 + 2)j

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If \nabla f = (2xy + \sin x)\bold{i} + (x^2 + 2)\bold{j}, your answer is correct.
 
but then why webassign say it's wrong...
 
I checked again and It still looks right to me. Maybe you read the question wrong, or entered it wrong.
 
pretty sure it's not wrong... hmmm
 
okay.. I think the answer is right, it's just the way I format the answer in webassign and it doesn't accepts it.. also if I am asked:

Find the exact change in f between (0, 0) and (1, π/2).

do I just plug the numbers in?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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