Solve for Pump Horsepower in 1-Inch Tube with No Heat Transfer

AI Thread Summary
The discussion focuses on calculating the horsepower required for a pump moving fluid through a 1-inch diameter tube, with given parameters of fluid density, flow rate, and pressure rise. The first law of thermodynamics is referenced, with the assumption of no heat transfer, leading to the conclusion that the change in enthalpy relates directly to the pressure and volumetric flow rate. Participants express confusion about unit conversions and the application of fluid dynamics principles, particularly in determining the velocity and power output. The calculation involves converting pressure from lbf/in to psf and using the relationship between horsepower and the rate of doing work. Ultimately, the solution requires careful consideration of the fluid's properties and the pump's efficiency.
MonkeyMouse
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Homework Statement


This was a thermodynamics question;
A fluid is being moved by a pump though a 1inch diameter tube. The density is 100 lb/ft3 with a flow of 12 lb/s. The pressure rises 40lbf/in. Assume there is no heat transfer. Find hp of the pump to the nearest 1/4hp.

Homework Equations



I assumed that the first law of thermodynamics was needed:
0=Qcv-wcv+m[(h1-h2)+(V12-V22)+g(z1-z2)]

The Attempt at a Solution



I assumed Q=0 but was rather confused on how to even start this equation. I believe you would need to use density relations to find the specific volume and enthalpy in order to apply the 1st law of thermodynamics? Would this be better suited to be solved in terms of fluid dynamics?
 
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MonkeyMouse said:

Homework Statement


This was a thermodynamics question;
A fluid is being moved by a pump though a 1inch diameter tube. The density is 100 lb/ft3 with a flow of 12 lb/s. The pressure rises 40lbf/in. Assume there is no heat transfer. Find hp of the pump to the nearest 1/4hp.

Homework Equations



I assumed that the first law of thermodynamics was needed:
0=Qcv-wcv+m[(h1-h2)+(V12-V22)+g(z1-z2)]

The Attempt at a Solution



I assumed Q=0 but was rather confused on how to even start this equation. I believe you would need to use density relations to find the specific volume and enthalpy in order to apply the 1st law of thermodynamics? Would this be better suited to be solved in terms of fluid dynamics?

It is said that, flow is 12 lb/s
So you can calculate the speed after the pump (you have diameter of the tube too)There is nothing about the speed before the pump, so we can assume it is zero.
Nothing is said about any diference in height of input/output too.
So

(z1-z2)=0

and because

2e9c7d6144b4cd931e5adc6efdfd4abe.png


and

ba3399371b47afbbb17d58d2c272ea18.png


you can easy calculate the power
η has to be 1, because it is said, there is no heat transfer

http://en.wikipedia.org/wiki/Pump
 
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Still pretty stuck, I am unsure how to get the change in P into psf from the units had once I incorporate the velocity?
 
What is the volumetric flow rate? Neglect the temperature rise. The rate of doing shaft work is equal to the rate of change of enthalpy for the mass going through the pump. Since there is no temperature change, it is just ΔP times the volumetric flow rate.
 
So just (5760lb/ft^2)(.12ft^2/s)... how would I get hp from those units?
 
MonkeyMouse said:
So just (5760lb/ft^2)(.12ft^2/s)... how would I get hp from those units?
1HP is 550 ft-lbs/sec.
 
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