Solve for the tension in T1 and T2

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The discussion revolves around solving for the tensions T1 and T2 in a physics problem involving angles and forces. The user initially struggles with the equations but proposes two equations: T1sin42 + T2sin18 = 0 and T1cos42 - T2cos18 = 0. After some corrections, they suggest the first equation should include a weight component, leading to T1sin42 + T2sin18 - 90 = 0. The user ultimately calculates T2 as approximately 65.93 and seeks confirmation on their method and understanding. The conversation highlights the process of applying trigonometric relationships to solve for unknown tensions in a static system.
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Homework Statement


A friend gave this to me and i have never taken physics could use some help on how to solve this.


Homework Equations


Have no clue


The Attempt at a Solution


Have researched and came up with this probably not correct
T1sin42+T2sin18=0
T1cos42-T2cos18=0
 

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You need to incorporate the force due to the hanging weight into the second equation.

EDIT: Sorry, the *first* equation! The vertical components.
 
Last edited:
lilgen said:

Homework Statement


A friend gave this to me and i have never taken physics could use some help on how to solve this.


Homework Equations


Have no clue


The Attempt at a Solution


Have researched and came up with this probably not correct
T1sin42+T2sin18=0
T1cos42-T2cos18=0

The first equation should be: T1sin42 + T2sin18 - 90 = 0.

Solve the second equation for T1 (in terms of T2). Plug that into the corrected first equation, and solve for T2. Then use that to find T1.
 
T1sin42+T2sin18-90=0
T1cos42-T2cos18=0

T1=T2cos18/cos42

T2cos18/cos42*sin12+sin18-90=0

T2=89.23
T1=157.92

Is this the way you were talking about doing it? I am wanting to learn it thank you for your help.
 
lilgen said:
T1sin42+T2sin18-90=0
T1cos42-T2cos18=0

T1=T2cos18/cos42

T2cos18/cos42*sin12+sin18-90=0

T2=89.23
T1=157.92

Is this the way you were talking about doing it? I am wanting to learn it thank you for your help.

T2(cos18/cos42*sin42+sin18)-90=0

Sorry about not following up.

I get T2=65.93 .
 
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