So sin(x + π/6) = √2/2luigihs said:Solve for x between 0 , and 2pi the next equation?
cos x + square root(3) sinx = square root(2)
sin(x+ (pi/6)) = 1/sqrt2 <-- but then I don't know what to do this what I think should do, but I am not sure how to solve x help me thanks!
jedishrfu said:You need to present your homework using the homework template where you state the problem, show some relevant formula that you might use to solve it and show an attempt.
I don't see how you got the sin(x+pi/6)=1/sqr(2) result from your original equation.
Mark44 said:So sin(x + π/6) = √2/2
Can you solve sin(u) = √2/2?
You've done all the hard work. The rest is easy.
Good advice. luigihs, the template is there for a reason - don't just blow it away...jedishrfu said:You need to present your homework using the homework template where you state the problem, show some relevant formula that you might use to solve it and show an attempt.
He divided both sides of the equation by 2 to get (1/2)sin(x) + (√3/2)cos(x) = √2/2, and then replaced 1/2 by cos(π/6) and √3/2 by sin(π/6). It would have been helpful if he had shown his steps.jedishrfu said:I don't see how you got the sin(x+pi/6)=1/sqr(2) result from your original equation.
Mark44 said:Good advice. luigihs, the template is there for a reason - don't just blow it away...
He divided both sides of the equation by 2 to get (1/2)sin(x) + (√3/2)cos(x) = √2/2, and then replaced 1/2 by cos(π/6) and √3/2 by sin(π/6). It would have been helpful if he had shown his steps.
The equation is "solve for x between 0 and 2pi". This means that we are looking for all possible values of x that satisfy the equation within that range.
To solve for x, you will need to use algebraic methods such as factoring, substitution, or the quadratic formula. It may also be helpful to graph the equation to visually see the solutions.
The range of 0 to 2pi is significant because it represents one full rotation around a circle in radians. This is commonly used in trigonometry and other mathematical concepts.
Yes, there may be restrictions or limitations depending on the specific equation. For example, the equation may only have real number solutions or may require certain values to be excluded from the solution set.
Yes, you can use a calculator to solve for x. However, it is important to make sure you are inputting the equation correctly and understanding how to interpret the calculator's output. It is always recommended to also check your solutions by hand.