Solve Gauss's Law and Flux: 55.3M Excess Electrons

AI Thread Summary
The discussion centers on calculating the net electric flux through a closed surface containing 55.3 million excess electrons. The key equation used is Φ = Qin/ε, where Qin represents the enclosed charge and ε is the permittivity constant (8.85 x 10^-12 F/m). Participants clarify that the excess electrons indicate a negative charge, which should be considered in the calculation of Qin. The solution involves multiplying the number of excess electrons by the elementary charge (-1.60 x 10^-19 C) to find Qin. The problem is ultimately resolved by applying the correct formula, demonstrating that the solution can be simpler than initially perceived.
dals2002
Messages
12
Reaction score
0
[SOLVED] Gauss's Law and Flux

ok so i have the biggest question of all i tried solving the following problem:

55.3 million excess electrons are inside a closed surface. What is the net electric flux through the surface?

now i tried the following equations:

\Phi= E . A = Qin/\epsilon

but i have the biggest question when there is excess electron does it mean that the electron field is negative, and if it does then that goes in Qin where then \Phi would be equal to Qin/\epsilon, and epsilon being 8.85*10 (permittivity constant)

well any help in solving this problem is very grateful
 
Last edited:
Physics news on Phys.org
You can solve for the enclosed charge, since the elementary charge of an electron (-1.60*10^-19 C) and the number of electrons is known. Just use Q/epsilon to solve for flux.
 
oh wow that was easy, i always see things harder then they are, thanks terbum
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Gauss' law problem -- Should the field due to both the inside and outside charges be taken into account?
Replies
28
Views
1K
No Electric Charges if No Electric Field in Region
Replies
22
Views
2K
Use of imaginary charge vs Gauss' law
Replies
12
Views
889
Flux due to a charge located at the corner of a cube
Replies
6
Views
3K
If closed integral of E.dS is zero over a surface, then...?
Replies
14
Views
851
Electric Flux for a cube problem
Replies
8
Views
3K
Question on a Gauss's Law problem
Replies
1
Views
1K
Gauss' law and Faraday cage problem
Replies
10
Views
2K
Electric Flux through the Face of a Cube
Replies
17
Views
8K
Gauss's law -- Integral form problem
Replies
3
Views
1K

Hot Threads

Recent Insights

Back
Top