Solve Heat Problem: Estimate Altitude, Rate of Heat Transfer

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The discussion revolves around solving a physics problem involving heat transfer and altitude estimation. The scientist measures steam temperature at 98°C, leading to calculated barometric height of 0.70 m and an altitude of approximately 8009 m based on air density. For part 'c', the user seeks assistance in calculating the rate of heat transfer from the camping stove to the water, using the formula Q = mcT. They have determined the mass of the water to be 2 kg but are uncertain about the initial temperature needed for the calculation. The final temperature is confirmed to be 98°C, prompting questions about the appropriate initial temperature to use.
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Homework Statement

A scientist carries a thermometer, barometer, pan and gas camping stove up a mountain. At a certain point he collects water from a stream, boils it and measures the temperature of the steam condensing on the thermometer to be 98°C. What is the height of the column of mercury (density = 13560 kg m–3) in the barometer?

b) Estimate the altitude of the scientist relative to sea level, assuming the density of air to be 1.186 kg m¬–3.

c)The scientist notices that it takes about 3 minutes to bring about 2 litres of water just to the boiling temperature. Assuming the thermal capacity of the water dominates (i.e. ignoring the thermal capacity of the pan), estimate the rate of heat transfer delivered by the camping stove to the pan of water.
I need help with part 'c', I have done parts 'a' and 'b'.

pressure at T = 98C is 0.093182MPa

a) \frac{p}{\rho g} = h = \frac{93182 pa}{9.81 \times 13560}

= 0.70 m

Usinf the same equation to get altitude, and the pressure in part a

b) \frac{p}{\rho g} = h = \frac{93182}{1.186 \times 9.81} = 8009m

How do I do part 'c'

Q = mcT?
I can work out the mass from the information given, m = \rho V = 0.002 \times 1000 = 2kg

However how do I get initial temperate?

Thank you.
 
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would the final temperature be 98C? So what is the intial temerature?
 
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